<!--
{
  "availability" : [
    "iOS: 8.0.0 -",
    "iPadOS: 8.0.0 -",
    "macCatalyst: 13.0.0 -",
    "macOS: 10.10.0 -",
    "tvOS: 9.0.0 -",
    "visionOS: 1.0.0 -",
    "watchOS: 2.0.0 -"
  ],
  "documentType" : "symbol",
  "framework" : "Swift",
  "identifier" : "/documentation/Swift/Array/removeAll(where:)-6bd6r",
  "metadataVersion" : "0.1.0",
  "role" : "Instance Method",
  "symbol" : {
    "kind" : "Instance Method",
    "modules" : [
      "Swift"
    ],
    "preciseIdentifier" : "s:SmsSMRzrlE9removeAll5whereySb7ElementSTQzKXE_tKF::SYNTHESIZED::s:Sa"
  },
  "title" : "removeAll(where:)"
}
-->

# removeAll(where:)

Removes all the elements that satisfy the given predicate.

```
mutating func removeAll(where shouldBeRemoved: (Self.Element) throws -> Bool) rethrows
```

## Parameters

`shouldBeRemoved`

A closure that takes an element of the
sequence as its argument and returns a Boolean value indicating
whether the element should be removed from the collection.

## Discussion

Use this method to remove every element in a collection that meets
particular criteria. The order of the remaining elements is preserved.
This example removes all the odd values from an
array of numbers:

```
var numbers = [5, 6, 7, 8, 9, 10, 11]
numbers.removeAll(where: { $0 % 2 != 0 })
// numbers == [6, 8, 10]
```

> Complexity: O(*n*), where *n* is the length of the collection.

---

Copyright &copy; 2026 Apple Inc. All rights reserved. | [Terms of Use](https://www.apple.com/legal/internet-services/terms/site.html) | [Privacy Policy](https://www.apple.com/privacy/privacy-policy)