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# max(by:)

Returns the maximum element in the sequence, using the given predicate
as the comparison between elements.

```
@warn_unqualified_access func max(by areInIncreasingOrder: (Self.Element, Self.Element) throws -> Bool) rethrows -> Self.Element?
```

## Parameters

`areInIncreasingOrder`

A predicate that returns `true` if its
first argument should be ordered before its second argument;
otherwise, `false`.

## Return Value

The sequence’s maximum element if the sequence is not empty;
otherwise, `nil`.

## Discussion

The predicate must be a *strict weak ordering* over the elements. That
is, for any elements `a`, `b`, and `c`, the following conditions must
hold:

- `areInIncreasingOrder(a, a)` is always `false`. (Irreflexivity)
- If `areInIncreasingOrder(a, b)` and `areInIncreasingOrder(b, c)` are
  both `true`, then `areInIncreasingOrder(a, c)` is also
  `true`. (Transitive comparability)
- Two elements are *incomparable* if neither is ordered before the other
  according to the predicate. If `a` and `b` are incomparable, and `b`
  and `c` are incomparable, then `a` and `c` are also incomparable.
  (Transitive incomparability)

This example shows how to use the `max(by:)` method on a
dictionary to find the key-value pair with the highest value.

```
let hues = ["Heliotrope": 296, "Coral": 16, "Aquamarine": 156]
let greatestHue = hues.max { a, b in a.value < b.value }
print(greatestHue)
// Prints "Optional((key: "Heliotrope", value: 296))"
```

> Complexity: O(*n*), where *n* is the length of the sequence.

---

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