Type Method

escapedTemplate(for:)

Returns a template string by adding backslash escapes as necessary to protect any characters that would match as pattern metacharacters

Declaration

class func escapedTemplate(for string: String) -> String

Parameters

string

The template string

Return Value

The escaped template string.

Discussion

Returns a string by adding backslash escapes as necessary to the given string, to escape any characters that would otherwise be treated as pattern metacharacters. You typically use this method to match on a particular string within a larger pattern.

For example, the string "(N/A)" contains the pattern metacharacters (, /, and ). The result of adding backslash escapes to this string is "\\(N\\/A\\)".

See Flag Options for the format of the resulting template string.

See Also

Escaping Characters in a String

class func escapedPattern(for: String) -> String

Returns a string by adding backslash escapes as necessary to protect any characters that would match as pattern metacharacters.