Get character from Unicode codepoint

Question

Created Oct ’18

Replies 2

Boosts 0

Views 1.3k

Participants 3

I use the following code to get a Character from a Unicode codepoiint:

let c = Character(Unicode.Scalar("12345")!)

It seems very complex and clumsy. Is there an shortcut way to achieve the same goal?

Answered by OOPer in 333870022

NO.

And the right syntax is

let c = Character(Unicode.Scalar(12345)!)

(`Unicode.Scalar("12345")!` causes runtime crash.)

If you often work with `Character` and Unicode codepoint, you can write an extension of your own.

extension Character {
    init?(_ codePoint: UInt32) {
        guard let us = Unicode.Scalar(codePoint) else {
            return nil
        }
        self = Character(us)
    }
}

print(Character(12345)!)

Or you can propose a new initializer of `Character` in swift.org .

Boost

Answer 1

OOPer OP

Oct ’18

Accepted Answer

NO.

And the right syntax is

let c = Character(Unicode.Scalar(12345)!)

(`Unicode.Scalar("12345")!` causes runtime crash.)

If you often work with `Character` and Unicode codepoint, you can write an extension of your own.

extension Character {
    init?(_ codePoint: UInt32) {
        guard let us = Unicode.Scalar(codePoint) else {
            return nil
        }
        self = Character(us)
    }
}

print(Character(12345)!)

Or you can propose a new initializer of `Character` in swift.org .

0

Answer 2

DTS Engineer OP

Apple

Oct ’18

Presumably you’re doing this a lot, and I’m curious why that is. Can you explain more of the backstory here?

When I run into issues like this I generally find it’s because I’m working in the wrong view. For example, if I’m parsing a string in a network protocol, it’s better to use the UTF-8 view. The code units are then

UInt8

, and I can initialise them from numeric values directly and from ASCII ‘character’ values using

init(ascii:)

.

Share and Enjoy
—
Quinn “The Eskimo!”
Apple Developer Relations, Developer Technical Support, Core OS/Hardware

let myEmail = "eskimo" + "1" + "@apple.com"

0