Type inference-related compiler segfault

Question

Created Sep ’15

Replies 3

Boosts 0

Participants 3

This little program will segfault the compiler (Xcode 7 beta 6):

let a = [1, 2, 3]
let b = a.map { $0 % 2 == 0 ? $0 : nil }
print(b)

Helping it with the type inference makes it compile and work as expected:

let a = [1, 2, 3]
let b : [Int?] = a.map { $0 % 2 == 0 ? $0 : nil }
print(b)

#22555889

Answered by ChrisLattner in 48429022

Thanks! This is indeed a bug and will be fixed in a subsequent update to the compiler.

-Chris

Boost

Answer 1

Sep ’15

FWIW in 1.2 swiftc returns this error:

error: cannot invoke 'map' with an argument list of type '((_) -> _)'

0

Answer 2

Sep ’15

Accepted Answer

Thanks! This is indeed a bug and will be fixed in a subsequent update to the compiler.

-Chris

0

Answer 3

Sep ’15

Tested with Xcode 7.1 beta 2, which gives an understandable error message for the first example. Problem solved.

0