SwiftyJSON JSON Object as a Class Property

Question

Created Jun ’15

Replies 3

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I am working with SwiftyJSON which is great. I am however having an issue with storing the JSON(data:) result in a property in my viewController. The standard use of SwiftyJSON works fine.

let json = JSON(data: data) let name = json[1]["name"].string

My problem occurs when I try to create a property to store the result of JSON(data:)

     var jsonData : JSON?


     someMethod()
     { 
          let json = JSON(data: data) 
          self.jsonData = json 
          if let name = self.jsonData[1]["name"].string 
          { 
               print(name) 
          } 
     }

When I do this I get an error on the following line.

if let name = self.jsonData[1]["name"].string

Cannot find member 'string'

Does anyone know why this is?

Answered by QuinceyMorris in 14548022

Using a fake JSON class definition, the following works in a playground:

if let name = self.jsonData?[1]["name"].string

I think the issue is that the 'let' "understands" the optionality in your jsonData property, but the chained operators inside the expression don't.

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Answer 1

QuinceyMorris OP

Jun ’15

Accepted Answer

Using a fake JSON class definition, the following works in a playground:

if let name = self.jsonData?[1]["name"].string

I think the issue is that the 'let' "understands" the optionality in your jsonData property, but the chained operators inside the expression don't.

0

Answer 2

JCT81 OP

Jun ’15

Brilliant. Thank you.

Take care,

Jon

0

Answer 3

tangplin OP

Aug ’15

Try:

var json: JSON = JSON.nullJSON


someMethod() 
     {  
          let json = JSON(data: data)  
          self.jsonData = json  
          if let name = self.jsonData[1]["name"].string  
          {  
               print(name)  
          }  
     }

0