Hello,
I want to extend a class B with code, but also want to make code available to it's superclass.
struct C<T> {
}
class A {
}
class B: A {
}
extension B where Self: A {
func foo() -> C<Self> {
fatalError()
}
}
How would I do that?
So why don't you extend the superclass ?
Code as is will not compile.
Dn't you want to define B as Protocol B, instead of class ?
But then I cannot inherit from A!
I don't understand your point:
class A {
var a: Int = 0
}
class B: A {
var b: Int = 0
}
extension A {
func show() {
print("a", a)
}
}
let someB = B()
print("someB", someB.a)
someB.a = 100
someB.show()
We get:
So B does get A extension, isn't it ?