Type 'Any' Has no Subscript Members, Swift 3

Question

MichaelMansour OP

Created Jan ’17

Replies 2

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Hi,
I try to update my Parse's App to Swift 3 but I stuck on the following error:

let likesNumber: AnyObject! = object.object(forKey: "Likes")![0]

Type "Any" has no subscript members

Can you help me ? Thanks a lot !

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Answer 1

MirekE OP

Jan ’17

Your "object" method apparently returns value of type Any. Any is not an array and does not have a subscript operator. You need to cast the returned value into an array (or any other appropriate type that supports subscripts).

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Answer 2

goldsdad OP

Jan ’17

object(forKey:) returns an Any? in Swift 3, so you'll need to try to cast the Any? to the type you're expecting, which I guess is NSArray, and, if successful, you'll then be able to subscript the array.

For example, likesNumber in the following code is an Int? :

let likesNumber = (object.object(forKey: "Likes") as? NSArray)?.firstObject as? Int // or whatever type is appropriate

If you prefer your app to crash if parsing doesn't go as expected, then use '!'s instead of '?'s, and likesNumber will be an Int if there is no crash.

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