Stored property 'base' of 'Sendable'-conforming struct 'AnyShape' has non-sendable type '(CGRect) -> Path'; this is an error in the Swift 6 language mode

Programming Languages Swift
bruno_mond OP
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Since I updated my project I'm getting this error

Stored property 'base' of 'Sendable'-conforming struct 'AnyShape' has non-sendable type '(CGRect) -> Path'; this is an error in the Swift 6 language mode

I get this error at that struct, more specifically on the base variable

public struct AnyShape: Shape {
    private var base: (CGRect) -> Path
    
    public init<S: Shape>(shape: S) {
        base = shape.path(in:)
    }
    
    public func path(in rect: CGRect) -> Path {
        base(rect)
    }
}

I have no idea how to solve this issue, I've been looking on the internet for same issues and get nothing yet

Answered by DTS Engineer in 805728022

Hello @bruno_mond,

There are a many different ways that you could address this issue, one alternative might be to store the shape itself (which is Sendable) instead of a reference to a function on the shape (which is not Sendable), for example:

public struct AnyShape: Shape {
    private var base: any Shape
    
    public init<S: Shape>(shape: S) {
        base = shape
    }
    
    public func path(in rect: CGRect) -> Path {
        base.path(in: rect)
    }
}

Having said that, you might want to consider if this "AnyShape" design is necessary, given that it effectively fills the same role as "any Shape".

Best regards,

Greg

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DTS Engineer OP
Apple
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Hello @bruno_mond,

There are a many different ways that you could address this issue, one alternative might be to store the shape itself (which is Sendable) instead of a reference to a function on the shape (which is not Sendable), for example:

public struct AnyShape: Shape {
    private var base: any Shape
    
    public init<S: Shape>(shape: S) {
        base = shape
    }
    
    public func path(in rect: CGRect) -> Path {
        base.path(in: rect)
    }
}

Having said that, you might want to consider if this "AnyShape" design is necessary, given that it effectively fills the same role as "any Shape".

Best regards,

Greg