Unable to remove bundle id even after app is removed from app store

Question

Created Sep ’24

Replies 3

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Participants 2

I removed my application from app store 4 days back. and now I am trying to delete app ID that is associated with it, but I am getting error as below:

"your app ID "xyz" appears to be in use by the app store, so it can not be removed at this time"

how can I resolve this and delete app ID successfully?

Answered by DTS Engineer in 803385022

how can I resolve this and delete app ID successfully?

You cannot.

Once App Store has a record of your App ID, it cannot be deleted. We call this out in Developer Account Help > Manage identifiers > Delete an App ID.

Why do you want to delete the App ID?

Share and Enjoy
—
Quinn “The Eskimo!” @ Developer Technical Support @ Apple
let myEmail = "eskimo" + "1" + "@" + "apple.com"

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Answer 1

DTS Engineer OP

Apple

Sep ’24

Recommended

how can I resolve this and delete app ID successfully?

You cannot.

Once App Store has a record of your App ID, it cannot be deleted. We call this out in Developer Account Help > Manage identifiers > Delete an App ID.

Why do you want to delete the App ID?

Share and Enjoy
—
Quinn “The Eskimo!” @ Developer Technical Support @ Apple
let myEmail = "eskimo" + "1" + "@" + "apple.com"

0

Answer 2

FTdeveloper OP

Sep ’24

I want to use this App ID from different developer account, but since it is already in use I am unable to. Is there any way I can just transfer it to another developer account?

0

Answer 3

DTS Engineer OP

Apple

Sep ’24

Is there any way I can just transfer it to another developer account?

Yes. That is the app transfer process, as described in App Store Connect Help > Transfer an app > Overview of app transfer.

IMO that only makes sense if you’ve published the app and have a bunch of users. If you’re working with an unpublished app, it’s much easier to just come up with a new App ID.

Share and Enjoy
—
Quinn “The Eskimo!” @ Developer Technical Support @ Apple
let myEmail = "eskimo" + "1" + "@" + "apple.com"

0