Your browser preventing this app to open “URL”

Hi Apple developers, I am very new to XCode and Swift, I am planning to build an app for iOS from a web. I tried to use WKWebView to handle the web , I managed to redirect some of the links to Safari, however some button/links didn't trigger .linkActivated function and encounter the error as "Your browser preventing this app to open “URL”. If I copy the URL to Safari is able to open, I trying to research on web but can't find any related solution for my case.

Here is the code in my app:

import UIKit import WebKit import SafariServices

class ViewController: UIViewController, WKNavigationDelegate {

var webView: WKWebView!

override func viewDidLoad() {
    super.viewDidLoad()
    
    // Initialize WKWebView
    let webConfiguration = WKWebViewConfiguration()
    //enable javascript
    webConfiguration.preferences.javaScriptEnabled = true
    webView = WKWebView(frame: self.view.frame, configuration: webConfiguration)
    webView.navigationDelegate = self
    self.view.addSubview(webView)
    
    // Load a web page as webview
    if let url = URL(string: "https://myurl") {
        let request = URLRequest(url: url)
        webView.load(request)
    }
    //console log
    webView.evaluateJavaScript("console.log('Button clicked!')") { result, error in
        if let error = error {
            print("Error executing JavaScript: \(error.localizedDescription)")
        } else {
            print("JavaScript result: \(String(describing: result))")
        }
    }
}   



func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
    
    if let url = navigationAction.request.url, navigationAction.navigationType == .linkActivated {
        // Check if URL is external and open it in Safari
        if UIApplication.shared.canOpenURL(url) {
            UIApplication.shared.open(url, options: [:], completionHandler: nil)
            decisionHandler(.cancel) // Prevent loading the link in the WebView
        } else {
            decisionHandler(.allow) // Allow loading if URL cannot be opened in Safari
        }
    } else {
        decisionHandler(.allow) // Allow the WebView to load the URL normally
    }
}    

}